document.write( "Question 87056: The logistic growth model P(t)=1270/1+27.22e^-0.348t represents the population of a bacterium in a culture tube after \"t\" hours.
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document.write( "A) What was the initial amount of bacteria in the population?
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document.write( "B)After how many hours is the population of bacteria 1000? Round to the nearest hour.
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document.write( "C) What is the limitig size of P(t), the poluation of bacterium? \r
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document.write( "* For B) I put 1000 in for \"P\" and C) I think the answer would be 1270...right? \n" );
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Algebra.Com's Answer #63025 by Nate(3500) ![]() You can put this solution on YOUR website! A) What was the initial amount of bacteria in the population? \n" ); document.write( "Initial amount would be determined after 0 hours ... t = 0 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Initial amount would be about 45 \n" ); document.write( "B)After how many hours is the population of bacteria 1000? Round to the nearest hour. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "C) What is the limitig size of P(t), the poluation of bacterium? \n" ); document.write( " \n" ); document.write( "Firstly, we would have to map out 1 + 27.22e^(-0.348t). Since time is positive, we must see how 1 + 27.22e^(-0.348t) reacts as \n" ); document.write( "Red: 1 + 27.22/e^(0.348t) \n" ); document.write( "Green: 1270/(1 + 27.22e^(-0.348t)) \n" ); document.write( " \n" ); document.write( "1270 is being divided by an exponentially smaller number every hour \n" ); document.write( "as 1 + 27.22/e^(0.348t) approaches infinity for time ... it equals 1 \n" ); document.write( "1270 / 1 is the limit \n" ); document.write( " |