document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013765>Question 1013765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jose paints a wall in 5 days. If Jose and Alfred works together fot at most 2 days, what must be the minimum rate of Alfred to complete the job ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630220 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call Alfred's solo time t.  The set up is like this<BR>\n" );
document.write( "2/5 + 2/t = 1<BR>\n" );
document.write( "Multiply by 5t and get<BR>\n" );
document.write( "2t + 10 = 5t<BR>\n" );
document.write( "10 = 3t<BR>\n" );
document.write( "t = 10/3 days </SPAN>\n" );
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