document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013833>Question 1013833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4.6\r<BR>\n" );
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document.write( "The following function is given.\r<BR>\n" );
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document.write( "f(x)=x^3 -5x^2 -9x+45\r<BR>\n" );
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document.write( "a. List all rational zeros that are possible according to the Rational Zero Theorem:\r<BR>\n" );
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document.write( "b. Use synthetic division to test several possible rational zeros in order to identify one actual zero<BR>\n" );
document.write( "   One rational zero of the given function is: \r<BR>\n" );
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document.write( "c. Use the zero from part (b) to find all the zeros of the polynomial function<BR>\n" );
document.write( "   The zeros of the function f(x)=x^3-5x^2 -9x+45 is: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630211 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630211\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^3 -5x^2 -9x+45=0<BR>\n" );
document.write( "rational zeros are +/- 1,3,5,9,15,and 45, the factors of the constant divided by the factors of x^3.<BR>\n" );
document.write( "using synthetic division with 3. By looking at the division, 1 did not look like it would work, so I went to 3.  If that didn't work, I would try -3. Then I would try 5 or -5.<BR>\n" );
document.write( "1;;;;-5;;;;-9;;;;-45<BR>\n" );
document.write( "1;;;;-2;;;;-15---0<BR>\n" );
document.write( "Therefore,(x-3) is a factor, and what is left over is  x^2-2x+15.  That factors to (x-5)(x+3).  <BR>\n" );
document.write( "roots are -3,3, and 5.<BR>\n" );
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document.write( " </SPAN>\n" );
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