document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013809>Question 1013809</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 11. Three times the larger minus 2 times the smaller equals 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630207 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the larger and the smaller, x and y.  Then we have<BR>\n" );
document.write( "x + y = 11  (or x = 11 - y) <BR>\n" );
document.write( "and\r<BR>\n" );
document.write( "\n" );
document.write( "3x - 2y = 8<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "3(11-y) - 2y = 8<BR>\n" );
document.write( "33 - 3y - 2y = 8<BR>\n" );
document.write( "-5y + 33 = 8<BR>\n" );
document.write( "-5y = -25<BR>\n" );
document.write( "y = 5<BR>\n" );
document.write( "x = 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );