document.write( "Question 1013807: A Norman window has the shape of a rectangle surmounted by a semicircle. If the perimeter of the window is 21 feet, express the area A of the window as a function of the width x (across the base) of the window. \n" ); document.write( "
Algebra.Com's Answer #630164 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
First find the perimeter of just
\n" ); document.write( "the semi-circular top of the window
\n" ); document.write( "\"+P%5B1%5D+=+%281%2F2%29%2A2%2Api%2A%28x%2F2%29+\" ( half of the perimeter of the circle )
\n" ); document.write( "\"+P%5B1%5D+=+pi%2A%28x%2F2%29+\"
\n" ); document.write( "------------------
\n" ); document.write( "Now subtract this result from \"+21+\" ft
\n" ); document.write( "\"+21+-+pi%2A%28x%2F2%29+\"
\n" ); document.write( "This result is twice the length of the rectangle
\n" ); document.write( "plus the width.
\n" ); document.write( "Let \"+y+\" = the length of the rectangle
\n" ); document.write( "\"+21+-+pi%2A%28x%2F2%29+=+2y+%2B+x+\"
\n" ); document.write( "\"+2y+=+21+-+pi%2A%28x%2F2%29+-+x+\"
\n" ); document.write( "\"+y+=+21%2F2+-+pi%2A%28+x%2F4+%29+-+x%2F2+\"
\n" ); document.write( "\"+y+=+21%2F2+-+pi%2A%28+x%2F4+%29+-+%282x%29%2F4+\"
\n" ); document.write( "\"+y+=+21%2F2+-+%28+pi+%2B+2+%29%2Ax%2F4+\"
\n" ); document.write( "-------------------------
\n" ); document.write( "The area of the rectangular part is:
\n" ); document.write( "\"+A%5B1%5D+=+x%2Ay+\"
\n" ); document.write( "\"+A%5B1%5D+=+%28+21x+%29%2F2+-+%28%28+pi+%2B+2+%29%2F4+%29%2Ax%5E2+\"
\n" ); document.write( "The area of the semi-circle is:
\n" ); document.write( "\"+A%5B2%5D+=+%281%2F2%29%2Api%2A%28+x%2F2+%29%5E2+\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\"+A%5B1%5D+%2B+A%5B2%5D+=+%28+21x+%29%2F2+-+%281%2F8%29%2A%28+pi+%2B+4+%29%2Ax%5E2+\"
\n" ); document.write( "Hope I got it!
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