document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013829>Question 1013829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the second side of a triangle is 3 times the first side. the third side is 2 and a half times the first side. the perimeter is 60 feet, find the length of each side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630133 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "F=first side; S=second side=3F; T=third side=2.5F<BR>\n" );
document.write( ".<BR>\n" );
document.write( "F+S+T=60ft<BR>\n" );
document.write( "F+3F+2.5F=60ft<BR>\n" );
document.write( "6.5F=60ft<BR>\n" );
document.write( "F=9.23ft<BR>\n" );
document.write( "S=3F=3(9.23ft)=27.69ft.<BR>\n" );
document.write( "T=2.5F=2.5(9.23)=23.08ft<BR>\n" );
document.write( ".<BR>\n" );
document.write( "ANSWER First side=9.23ft; Second side=27.69ft; Third side=23.08ft </SPAN>\n" );
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