document.write( "Question 1013843: Mrs,Perez is 3 times as old as her son, jaypee in 12 years,Mrs Perez will be twice as old as Kaylee.
\n" );
document.write( "What is the present age. Thank you.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #630126 by ikleyn(52794)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Mrs,Perez is 3 times as old as her son, Jaypee. In 12 years, Mrs. Perez will be twice as old as Kaylee. What is the present age. Thank you. \n" ); document.write( "----------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let P = Mrs. Perez' present age,\r\n" ); document.write( " J = Jaypee --- \" -----.\r\n" ); document.write( "\r\n" ); document.write( "Then you have two equations\r\n" ); document.write( "\r\n" ); document.write( "P = 3J,\r\n" ); document.write( "P + 12 = 2(J+12).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Substitute (1) into (2). You will get\r\n" ); document.write( "\r\n" ); document.write( "3J + 12 = 2(J+12 ---> 3J + 12 = 2J + 24 ---> 3J - 2J = 24 - 12 ---> J = 12.\r\n" ); document.write( "\r\n" ); document.write( "Answer. J = 12, P = 36.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |