document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87020>Question 87020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. Instructions read- construct an algebraic relationship for this problem. Monthly water bill is equal to $55 for the first 6000 gallons (or any portion thereof) plus the number of gallons used in excess of 6000 gallons times $0.20 per gallon. Thanks for your help<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63012 by </B><A HREF=/tutors/aboutme.mpl?userid=scianci><B>scianci(186)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scianci><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = total # of gallons. The first 6000 gallons are billed a fixed $55. Add to this the # of gallons over 6000 (total - 6000) times 0.2 </SPAN>\n" );
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