document.write( "Question 1013789: need to write an equation and solve\r
\n" ); document.write( "\n" ); document.write( "Nancy takes an hour and a half to rake the lawn, but it takes her only 40 minutes if her sister rakes, too. How long does it take her sister to rake the lawn alone?
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Algebra.Com's Answer #630085 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "Nancy takes an hour and a half to rake the lawn, but it takes her only 40 minutes if her sister rakes, too. How long does it take her sister to rake the lawn alone?
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document.write( "Nansy's raking rate is \"1\" : \"1\"\"1%2F2\" = \"2%2F3\" of-the-lawn-per-hour.\r\n" );
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document.write( "Let x be raking rate of her sister in the same units of \"lawn%2Fhour\".\r\n" );
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document.write( "Then their joint rate is \"x+%2B+2%2F3\" of-the-lawn-per-hour.\r\n" );
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document.write( "The equation is \r\n" );
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document.write( "\"1%2F%28x%2B2%2F3%29\" = \"40%2F60\" = \"2%2F3\",   or   (\"40%2F60\" is 40 minutes of time in hours).\r\n" );
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document.write( "Multiply both sides by 3*(x+2/3). You will get\r\n" );
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document.write( "3 = 2*(x+2/3),   or   3 = 2x + 4/3,   or  2x = 3 - \"4%2F3%7D%7D+=+%7B%7B%7B9%2F3-4%2F3\" = \"5%2F3\".\r\n" );
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document.write( "Hence, x = \"5%2F6\".\r\n" );
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document.write( "It is the sister's rate. \r\n" );
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document.write( "Therefore, it will take \"1%2Fx\" = \"1%2F%285%2F6%29\" = \"6%2F5\" hours = 1 hour 12 minutes for the sister to rake the lawn working alone.\r\n" );
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