document.write( "Question 1013750: The manager of a store that specializes in selling tea decides to experiment with a new blend. She will mix some Earl Gray tea that sells for $4 a pound with some Orange Pekoe tea that sells for $2 a pound to get 900 pounds of the new blend. The selling price of the new blend is to 2.50 per pound, and there is to be no difference in revenue from selling the new blend versus selling the other types. How many pounds of the Earl Gray and Orange Pekoe tea are required? \n" ); document.write( "
Algebra.Com's Answer #630051 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = pounds of Earl Gray needed
\n" ); document.write( "Let \"+b+\" = pounds of Orange Pekoe needed
\n" ); document.write( "------------------------------------
\n" ); document.write( "(1) \"+a+%2B+b+=+900+\"
\n" ); document.write( "(2) \"+%28+4a+%2B+2b+%29+%2F+900+=+2.5+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "(2) \"+4a+%2B+2b+=+2.5%2A900+\"
\n" ); document.write( "(2) \"+4a+%2B+2b+=+2250+\"
\n" ); document.write( "(2) \"+2a+%2B+b+=+1125+\"
\n" ); document.write( "---------------------
\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) \"+2a+%2B+b+=+1125+\"
\n" ); document.write( "(1) \"+-a+-+b+=+-900+\"
\n" ); document.write( "--------------------
\n" ); document.write( "\"+a+=+225+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+a+%2B+b+=+900+\"
\n" ); document.write( "(1) \"+225+%2B+b+=+900+\"
\n" ); document.write( "(1) \"+b+=+675+\"
\n" ); document.write( "225 pounds of Earl Gray are needed
\n" ); document.write( "675 pounds of Orange Pekoe are needed
\n" ); document.write( "------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+4a+%2B+2b+%29+%2F+900+=+2.5+\"
\n" ); document.write( "(2) \"+%28+4%2A225+%2B+2%2A675+%29+%2F+900+=+2.5+\"
\n" ); document.write( "(2) \"+%28+900+%2B+1350+%29+%2F+900+=+2.5+\"
\n" ); document.write( "(2) \"+2250+=+2.5%2A900+\"
\n" ); document.write( "(2) \"+2250+=+2250+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );