document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013673>Question 1013673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one root of the equation x^2+px+q=0 is twice of the second root, then prove that 2p^2=9q. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629992 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> quadratic formula<BR>\n" );
document.write( "x=(1/2)(-p+sqrt(p^2-4q)) and that is 2*(1/2) (-p-sqrt (p^2-4q))<BR>\n" );
document.write( "multiply both sides by 2<BR>\n" );
document.write( "-p+sqrt(p^2-4q)=2*(-p-sqrt(p^2-4q))<BR>\n" );
document.write( "-p+sqrt(p^2-4q)=-2p-2sqrt(p^2-4q)<BR>\n" );
document.write( "p=-3 sqrt(p^2-4q)<BR>\n" );
document.write( "square both sides<BR>\n" );
document.write( "p^2=9 (p^2-4q)=9p^2-36q<BR>\n" );
document.write( "-8p^2= -36 q<BR>\n" );
document.write( "2p^2=9q\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );