document.write( "Question 1013590: A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account?
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Algebra.Com's Answer #629985 by fractalier(6550)\"\" \"About 
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Call x the amount he invested at 2%. Thus he invested x+800 at 4%.
\n" ); document.write( "The setup looks like this then:
\n" ); document.write( ".02x + .04(x+800) = 92
\n" ); document.write( ".02x + .04x + 32 = 92
\n" ); document.write( ".06x = 60
\n" ); document.write( "x = $1000 at 2%
\n" ); document.write( "which means
\n" ); document.write( "800+x = $1800 at 4%
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