document.write( "Question 1013590: A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account?
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Algebra.Com's Answer #629985 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call x the amount he invested at 2%. Thus he invested x+800 at 4%. \n" ); document.write( "The setup looks like this then: \n" ); document.write( ".02x + .04(x+800) = 92 \n" ); document.write( ".02x + .04x + 32 = 92 \n" ); document.write( ".06x = 60 \n" ); document.write( "x = $1000 at 2% \n" ); document.write( "which means \n" ); document.write( "800+x = $1800 at 4% \n" ); document.write( " |