document.write( "Question 1013684: 4x^2-3x-4=0 \n" ); document.write( "
Algebra.Com's Answer #629957 by rothauserc(4718)\"\" \"About 
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4x^2 -3x -4 = 0
\n" ); document.write( "divide both sides of = by 4
\n" ); document.write( "x^2 -3x/4 -1 = 0
\n" ); document.write( "x^2 -3x/4 = 1
\n" ); document.write( "complete the square
\n" ); document.write( "x^2 -3x/4 +9/64 = 1 + 9/64
\n" ); document.write( "(x - 3/8)^2 = 64/64 + 9/64 = 73/64
\n" ); document.write( "x - 3/8 = (3/8) * sqrt(7)
\n" ); document.write( "x = (3/8) + ((3/8) * sqrt(7))
\n" ); document.write( "x = (3/8) * (1 + or - sqrt(7))
\n" ); document.write( "therefore
\n" ); document.write( "x = (3/8) * (1 + sqrt(7))
\n" ); document.write( "or
\n" ); document.write( "x = (3/8) * (1 - sqrt(7))
\n" ); document.write( " \n" ); document.write( "
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