document.write( "Question 1013618: Explain in words how to write an equation that is part one: parallel and then also part two: perpendicular to the equation y=2/3x-4 passing through the point (-2,-5). Write your answer in standard form. \n" ); document.write( "
Algebra.Com's Answer #629894 by josgarithmetic(39618)\"\" \"About 
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Reference equation given, \"y=%282%2F3%29x-4\". Slope is \"2%2F3\".
\n" ); document.write( "A line in the plane parallel also has slope \"2%2F3\"; and a line in the plane perpendicular to the reference line has slope negative reciprocal, which is \"-3%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "The parallel line through the given point (-2,-5) is \"y-%28-5%29=%282%2F3%29%28x-%28-2%29%29\" which is written in point-slope form.\r
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\n" ); document.write( "\n" ); document.write( "The perpendicular line through the given point is \"y-%28-5%29=%28-3%2F2%29%28x-%28-2%29%29\", again being in point-slope form.\r
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\n" ); document.write( "\n" ); document.write( "Starting those in point-slope form was easier than arranging for slope-intercept form. Use your algebra skill to put each of them into standard form.
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