document.write( "Question 1013597: Newport and Vernonville are 112 miles apart. A car leaves Newport traveling towards Vernonville, and another car leaves Vernonville at the same time, traveling towards Newport. The car leaving Newport averages 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What are the average speeds of the car?
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document.write( "The car leaving Newport averages ___ miles per hour
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document.write( "The car leaving Vernonville averages ___ miles per hour \n" );
document.write( "
Algebra.Com's Answer #629879 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Newport and Vernonville are 112 miles apart. A car leaves Newport traveling towards Vernonville, and another car leaves Vernonville at the same time, traveling towards Newport. The car leaving Newport averages 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What are the average speeds of the car? \n" ); document.write( "The car leaving Newport averages 40 miles per hour \n" ); document.write( "The car leaving Vernonville averages 30 miles per hour\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " x= epeed of car leaving Vernonville \n" ); document.write( "x+10= epeed of car leavingNewport \n" ); document.write( "1 hr and 36 min=1.6 hr \n" ); document.write( "The two cars are traveling toward each other at the sum of the two speeds=x+x+10=2x+10 \n" ); document.write( "distance/speed=travel time \n" ); document.write( "112/(2x+10)=1.6 \n" ); document.write( "3.2x+16=112 \n" ); document.write( "3.2x=96 \n" ); document.write( "x=30 \n" ); document.write( "x+10=40 \n" ); document.write( " |