document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87003>Question 87003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve my assignment. Thank you.<BR>\n" );
document.write( "Points N, R and T lie in a straight line. R lies between N and T. If RT = 4/3 NT<BR>\n" );
document.write( "and RT = 100, find NT. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62987 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> RT CANNOT BE GREATER [4/3=1.333] THAN NT IF R IS BETWEEN N&T<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "RT=100 & RT=(4/3)NT THEN<BR>\n" );
document.write( "100=(4/3)NT<BR>\n" );
document.write( "NT=100/(4/3)<BR>\n" );
document.write( "NT=100(3/4)<BR>\n" );
document.write( "NT=300/4<BR>\n" );
document.write( "NT=75 <BR>\n" );
document.write( "THE ENTIRE LENGTH OF THE LINE (NT=75) CANNOT BE LONGER THAN THE PART (RT=100)  <BR>\n" );
document.write( " </SPAN>\n" );
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