document.write( "Question 87017: Sketch the graph of the following functions
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Algebra.Com's Answer #62981 by jim_thompson5910(35256)\"\" \"About 
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Start with the graph of \"y=x%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C500%2C-10%2C10%2C-10%2C10%2C+x%5E3%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Since we have \"%28x-2%29%5E3\" this means we shift the graph 2 units to the right.
\n" ); document.write( "So shift the graph 2 units to the right like this:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C500%2C-10%2C10%2C-10%2C10%2C+x%5E3%2C+%28x-2%29%5E3%29+\" Graph of \"y=x%5E3\" (red) and \"y=%28x-2%29%5E3\" (green)\r
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\n" ); document.write( "\n" ); document.write( "Now since we're adding 2 to \"y=%28x-2%29%5E3\" to get \"y=%28x-2%29%5E3%2B2\" this means we shift the graph \"y=%28x-2%29%5E3\" up two units like this\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C500%2C-10%2C10%2C-10%2C10%2C+x%5E3%2C+%28x-2%29%5E3%2C+%28x-2%29%5E3%2B2%29+\" Graph of \"y=x%5E3\" (red) , \"y=%28x-2%29%5E3\" (green), and \"y=%28x-2%29%5E3%2B2\" (blue)\r
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\n" ); document.write( "\n" ); document.write( "So the graph of \"y=%28x-2%29%5E3%2B2\" is \r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C500%2C-10%2C10%2C-10%2C10%2C%28x-2%29%5E3%2B2%29+\" Graph \"y=%28x-2%29%5E3%2B2\"
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