document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013502>Question 1013502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the following equation is given, what is the value of sec(x)?<BR>\n" );
document.write( "(cot(x)/tan(x)) - (csc(x)/sin(x)) = (2/sec(x)) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629792 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the following equation is given, what is the value of sec(x)?<BR>\n" );
document.write( "(cot(x)/tan(x)) - (csc(x)/sin(x)) = 2/sec(x)<BR>\n" );
document.write( "cot^2 - csc^2 = 2/sec<BR>\n" );
document.write( "cos^2/sin^2 - 1/sin^2 = 2/sec<BR>\n" );
document.write( "(cos^2 - 1)/sin^2 = 2/sec<BR>\n" );
document.write( "(cos^2 - 1)/(1 - cos^2) = 2/sec<BR>\n" );
document.write( "2/sec = -1<BR>\n" );
document.write( "sec(x) = -2<BR>\n" );
document.write( " </SPAN>\n" );
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