document.write( "Question 1013457: a parabolic arch has a width of 18 m across the bottom. at a vertical distance 3 m above the bottom, the width across the arch is 12 m. what is the height of the arch in meters? \n" ); document.write( "
Algebra.Com's Answer #629784 by Alan3354(69443)\"\" \"About 
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a parabolic arch has a width of 18 m across the bottom. at a vertical distance 3 m above the bottom, the width across the arch is 12 m. what is the height of the arch in meters?
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\n" ); document.write( "Plot the points (-9,0) and (9,0) for the bottom.
\n" ); document.write( "2 other points are (-6,3) and (6,3)
\n" ); document.write( "----
\n" ); document.write( "The form is y = -ax^2 + c
\n" ); document.write( "0 = -a*81 + c
\n" ); document.write( "3 = -a*36 + c
\n" ); document.write( "----------------- Subtract
\n" ); document.write( "-3 = -45a
\n" ); document.write( "a = 1/15
\n" ); document.write( "=================
\n" ); document.write( "0 = -81/15 + c
\n" ); document.write( "c = 5.4
\n" ); document.write( "===============
\n" ); document.write( "--> \"y+=+-x%5E2%2F15+%2B+5.4\"
\n" ); document.write( "Height of the arch at the center = 5.4 meters
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