document.write( "Question 1013490: The three Smith children have a combined age of 50. The youngest is half as old as the oldest. Ten years ago, the oldest was 7 times as the youngest. How old were the children ten years ago? (3 answers)\r
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Algebra.Com's Answer #629775 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Let the youngest child be x. The next kids are y and z. We have \n" ); document.write( "x + y + z = 50 \n" ); document.write( "x = (1/2)z or z = 2x \n" ); document.write( "z-10 = 7(x-10) \n" ); document.write( "Substituting we have \n" ); document.write( "2x - 10 = 7(x - 10) \n" ); document.write( "2x - 10 = 7x - 70 \n" ); document.write( "5x = 60 \n" ); document.write( "x = 12 (youngest) \n" ); document.write( "z = 2(12) = 24 (oldest) \n" ); document.write( "y = 50 - 12 - 24 = 14 (middle) \n" ); document.write( " |