document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013468>Question 1013468</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify the following expression <BR>\n" );
document.write( "(1 - csc^2(theta)) / (cot (theta))<BR>\n" );
document.write( "I believe I have the answer but I can't tell if it is supposed to be -cot(theta) or just cot(theta).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629729 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is - cot (theta)<BR>\n" );
document.write( "1-1/sin^2 theta=numerator.  That is (sin^2 theta-1)/sin^2.<BR>\n" );
document.write( "1-sin^2 theta is cos^2 theta<BR>\n" );
document.write( "-(sin^2 theta-1)=1-sin^2 theta.<BR>\n" );
document.write( "Therefore -cos^2 theta/sin^2 theta is numerator<BR>\n" );
document.write( "Divide by cos theta/sin theta.<BR>\n" );
document.write( "That give -cos theta/sin theta=-cot theta. </SPAN>\n" );
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