document.write( "Question 1013409: I think this is a linear equation, but anyways, here's the problem:\r
\n" ); document.write( "\n" ); document.write( "The length of a room is four times its width. If the perimeter is 250 feet, what are the dimensions of the room? I set up two equations:\r
\n" ); document.write( "\n" ); document.write( "1) 4l +w=250
\n" ); document.write( "2) l -w =0\r
\n" ); document.write( "\n" ); document.write( "I used the method of elimination and ended up with:\r
\n" ); document.write( "\n" ); document.write( "5l = 250 and then I divided by 5.\r
\n" ); document.write( "\n" ); document.write( "The result was l = 50. I divided that by 4 and got 12.5 inches which I presumed was the measurement of the width. My final answer was:\r
\n" ); document.write( "\n" ); document.write( "l=50 in and w=12.5 in (there is no dimension specified, but I used inches)\r
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\n" ); document.write( "\n" ); document.write( "Am I correct, or was I supposed to plug 50 back in to the original equation?\r
\n" ); document.write( "\n" ); document.write( "Thanks for helping, and please show your work!
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Algebra.Com's Answer #629666 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The character which looks like the ONE digit is a very bad choice for a variable because it interferes with reading.\r
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\n" ); document.write( "\n" ); document.write( "L for length, w for width.
\n" ); document.write( "The length of a room is four times its width,
\n" ); document.write( "\"L=4w\";\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "...perimeter is 250 feet.
\n" ); document.write( "\"2L%2B2w=250\"
\n" ); document.write( "\"L%2Bw=125\"
\n" ); document.write( "\"4w%2Bw=125\" by substitution;
\n" ); document.write( "\"5w=125\"
\n" ); document.write( "\"highlight%28w=25%29\"
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