document.write( "Question 1013409: I think this is a linear equation, but anyways, here's the problem:\r
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document.write( "The length of a room is four times its width. If the perimeter is 250 feet, what are the dimensions of the room? I set up two equations:\r
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document.write( "1) 4l +w=250
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document.write( "2) l -w =0\r
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document.write( "I used the method of elimination and ended up with:\r
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document.write( "5l = 250 and then I divided by 5.\r
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document.write( "The result was l = 50. I divided that by 4 and got 12.5 inches which I presumed was the measurement of the width. My final answer was:\r
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document.write( "l=50 in and w=12.5 in (there is no dimension specified, but I used inches)\r
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document.write( "Am I correct, or was I supposed to plug 50 back in to the original equation?\r
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document.write( "Thanks for helping, and please show your work! \n" );
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Algebra.Com's Answer #629666 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! The character which looks like the ONE digit is a very bad choice for a variable because it interferes with reading.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L for length, w for width. \n" ); document.write( "The length of a room is four times its width, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "...perimeter is 250 feet. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |