document.write( "Question 1013307: jimmy's sister is twice as old as he is. his big brother is 5 years older than he is. the sum of their three ages is 29. How old is jimmy's brother? \n" ); document.write( "
Algebra.Com's Answer #629580 by macston(5194) You can put this solution on YOUR website! . \n" ); document.write( "J=Jimmy's age; S=sister's age=2J; B=brother's age=J+5 \n" ); document.write( ". \n" ); document.write( "J+S+B=29 \n" ); document.write( "J+(2J)+(J+5)=29 \n" ); document.write( "4J+5=20 \n" ); document.write( "4J=24 \n" ); document.write( "J=6 \n" ); document.write( "Jimmy is 6 years old \n" ); document.write( ". \n" ); document.write( "B=J+5=6+5=11 \n" ); document.write( "ANSWER: Jimmy's brother is 11 years old. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "S=2J=2(6)=12 \n" ); document.write( "Jimmy's sister is 12 years old. \n" ); document.write( ". \n" ); document.write( "J+S+B=29 \n" ); document.write( "6+12+11=29 \n" ); document.write( "29=29 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |