document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86997>Question 86997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mandy begins bicycling W at 20mph. Liz leaves from the same pont 1 hour later bicycling west at 30 mph.  When will she catch up with Mandy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62951 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mandy has a 20 mi (and 1 hour) head start ... Liz goes 10 mph faster so in 2 hours she will catch up\r<BR>\n" );
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document.write( "using rate*time=distance ... let x equal Liz's time ...the distances are equal ... 20(x+1)=30(x)\r<BR>\n" );
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document.write( "20x+20=30x ... 20=10x ... 2=x </SPAN>\n" );
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