document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013233>Question 1013233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car travels a distance of900 km with a certain average speed. After travelling half the distance, if the average speed of the car is increased by 15 km/hr,the time required to travel the remaining distance is reduced by 3/2 hours.find the original average speed or the car. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629508 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A car travels a distance of900 km with a certain average speed. After travelling half the distance, if the average speed of the car is increased by 15 km/hr,the time required to travel the remaining distance is reduced by 3/2 hours.find the original average speed or the car.<BR>\n" );
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document.write( "r = lower speed in km/hr<BR>\n" );
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document.write( "450/r = 450/(r+15) + 3/2<BR>\n" );
document.write( "300/r = 300/(r+15) + 1 = (315+r)/(r+15)<BR>\n" );
document.write( "r*(315+r) = 300*(r+15)<BR>\n" );
document.write( "r^2 + 315r = 300r + 4500<BR>\n" );
document.write( "r^2 + 15r - 4500 = 0<BR>\n" );
document.write( "r = 60 km/hr\r<BR>\n" );
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document.write( " </SPAN>\n" );
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