document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86740>Question 86740</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0471662933/algebrahomeworkh>Mathematics for elementary teachers</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this problem.  The problem states:<BR>\n" );
document.write( "Two digits of this number were erased: 273*49*5.  However we know that 9 and 11 divide the number. What is it?\r<BR>\n" );
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document.write( "What I have done so far:<BR>\n" );
document.write( "2+7+3+*+4+9+*+5 = 30+*+*\r<BR>\n" );
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document.write( "The only number divisible by both 9 and 11 is 99. However, to make the sum of this number equal 99 the two digits would have to be 35 and 34.  I am not sure if these numbers qualify?  I tried other single numbers and haven't found a sum divided by both 9 and 11.  \r<BR>\n" );
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document.write( "Your help would be most appreciated.  Thanks.<BR>\n" );
document.write( "Sincerely,<BR>\n" );
document.write( "R. Franke </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62949 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x equal the missing thousands digit and y equal the missing tens digit\r<BR>\n" );
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document.write( "a number is divisible by 9 if the sum of the digits is divisible by 9 ... so 30+x+y=36 or 30+x+y=45 ... x+y=6 or x+y=15\r<BR>\n" );
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document.write( "a number is divisible by 11 if the difference between the sum of the odd numbered digits and the sum of the even numbered digits is divisible by 11 ... so 2+3+4+y-(7+x+9+5) or y-x-12=-11 ... y-x=1 ... this means an ODD sum\r<BR>\n" );
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document.write( "x+y=15 ... y-x=1 ... 2y=16 ... y=8 ... x=7\r<BR>\n" );
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document.write( " </SPAN>\n" );
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