document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013228>Question 1013228</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mario and Julio are working together to detail cars. When they work together they can wash 7 cars in 2 hours. If Mario works alone he can detail 5 cars in 3 hours. If Julio works alone, how long will it take him to detail 12 cars? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629474 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mario: 5 cars/3 hours=5/3 cars per hour<BR>\n" );
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document.write( "Together: 7 cars /2 hours <BR>\n" );
document.write( "In 2 hours Mario details 2hrs(5/3 car/hr)=10/3 cars <BR>\n" );
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document.write( "7 cars-10/3 cars=21/3 cars-10/3 cars=11/3 cars<BR>\n" );
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document.write( "When working together for 2 hours, Mario details 10/3 cars, leaving 11/3 cars for Julio.<BR>\n" );
document.write( "Thus Julio: 11/3 cars/2 hours=11/6 cars per hour.<BR>\n" );
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document.write( "For Julio to detail 12 cars:<BR>\n" );
document.write( "12 cars /(11/6 cars/hr)=6.55 hours<BR>\n" );
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document.write( "ANSWER: It would take Julio 6.55 hours to detail 12 cars.<BR>\n" );
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