document.write( "Question 1013191: Moe and Joe take a car trip. Moe drives at an average speed of 41 mph for the first hour and then they stop for gas for 10 minutes. After filling gas, Joe drives at an average speed of 27 mph for 40 minutes, and then the traffic clears and he gets to drive at an average speed of 60 mph for half hour. Find the average speed of the car on this trip.
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document.write( "Express your answer in mph to two significant figures.\r
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document.write( "I have tried finding individual distances by multiplying each mph by hr in order to get these and adding all of them together to get a total distance which comes out as 90 miles total. Then I added total times in minutes so 60 min+10 min etc. and I got 140 min. Then I divided 90 miles by 2.33 hrs which came out as 38.6. My answer with significant figures would be 39 but it is wrong. \n" );
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Algebra.Com's Answer #629417 by MathTherapy(10555)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Moe and Joe take a car trip. Moe drives at an average speed of 41 mph for the first hour and then they stop for gas for 10 minutes. After filling gas, Joe drives at an average speed of 27 mph for 40 minutes, and then the traffic clears and he gets to drive at an average speed of 60 mph for half hour. Find the average speed of the car on this trip. \n" ); document.write( "Express your answer in mph to two significant figures.\r \n" ); document.write( "\n" ); document.write( "I have tried finding individual distances by multiplying each mph by hr in order to get these and adding all of them together to get a total distance which comes out as 90 miles total. Then I added total times in minutes so 60 min+10 min etc. and I got 140 min. Then I divided 90 miles by 2.33 hrs which came out as 38.6. My answer with significant figures would be 39 but it is wrong. \n" ); document.write( " Distance covered, driving at 41 mph: 41 * 1 = 41 miles\n" ); document.write( " |