document.write( "Question 1013098: a glass tube 1.5m tall is filled with liquid of density 1080kgm what pressure exerted on the base of the tube if the atmospheric pressure is 101kpa?[g=10m/s] \n" ); document.write( "
Algebra.Com's Answer #629410 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "A glass tube 1.5 m tall is filled with liquid of density 1080 \"kg%2Fm%5E3\". What pressure exerted on the base of the tube if the atmospheric pressure is 101 kpa? [g=10 m/s]
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document.write( "The pressure a column of liquid exerts on the bottom is \r\n" );
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document.write( "P = \"rho%2Ag%2Ah\",\r\n" );
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document.write( "where \"rho\" is the liquid density, g is acceleration due to gravity and h is the height of the column of the liquid.\r\n" );
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document.write( "So, in your case P = 1080*10*1.5 = 16200 kpa.\r\n" );
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document.write( "To account for the atmospheric pressure add it (101 kpa).\r\n" );
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document.write( "But keep in mind that the same atmospheric pressure acts to the bottom from the outside \r\n" );
document.write( "  (until special measures are taken to isolate the bottom from the atmosphere).\r\n" );
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