document.write( "Question 86978: This question is really bothering me. Please help. Express f(x) = x2 + │x+3│ - 1 without the absolute values and hand-graph.\r
\n" ); document.write( "\n" ); document.write( " Hint: │x│= x if x ≥ 0 or\r
\n" ); document.write( "\n" ); document.write( " = –x if x < 0 \n" ); document.write( "
Algebra.Com's Answer #62938 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Express f(x) = x^2 + │x+3│ - 1 without the absolute values and hand-graph.
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\n" ); document.write( "Note:
\n" ); document.write( "|x+3| = x+3 if x+3>=0; that is x>=-3
\n" ); document.write( "|x+3| = -(x+3) if x+3 <0; that is x<-3
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\n" ); document.write( "So, for x<-3 your equation becomes:
\n" ); document.write( "f(x) = x^2 -x-3-1
\n" ); document.write( "f(x) = x^2-x-4
\n" ); document.write( "Graph this parabola to the left of x=-3.
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\n" ); document.write( "And for x>=-3 you equation becomes:
\n" ); document.write( "f(x) = x^2+x+3-1
\n" ); document.write( "f(x) = x^2+x+2
\n" ); document.write( "Graph this parabola at and to the right of x=-3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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