document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013157>Question 1013157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve log(3x+1) - log(2x+3) = log 2 by graphing. Then solve the equation by using the Exponential - Logarithmic Properties. Explain the result.<BR>\n" );
document.write( "Please include steps :D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629372 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I cannot graph this here, but I can help you solve it...<BR>\n" );
document.write( "log(3x+1) - log(2x+3) = log 2<BR>\n" );
document.write( "log((3x+1)/(2x+3)) = log 2<BR>\n" );
document.write( "(3x+1)/(2x+3) = 2<BR>\n" );
document.write( "3x + 1 = 2(2x + 3)<BR>\n" );
document.write( "3x + 1 = 4x + 6<BR>\n" );
document.write( "x = -5<BR>\n" );
document.write( "But there are no logs of negative numbers, so there is no solution... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );