document.write( "Question 1013154: What is the answer to x+2y=10
\n" ); document.write( " 2x-y=5? using the substitution method?
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Algebra.Com's Answer #629358 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"x%2B2y=10\".........eq.1
\n" ); document.write( "\"2x-y=5\"..........eq.2
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\n" ); document.write( "\n" ); document.write( "using the substitution method, first solve \"x%2B2y=10\".........eq.1 for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=10-2y\".........substitute it in eq.2\r
\n" ); document.write( "\n" ); document.write( "\"2%2810-2y%29-y=5\"........solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"20-4y-y=5\"\r
\n" ); document.write( "\n" ); document.write( "\"20-5y=5\"\r
\n" ); document.write( "\n" ); document.write( "\"20-5=5y\"\r
\n" ); document.write( "\n" ); document.write( "\"15=5y\"\r
\n" ); document.write( "\n" ); document.write( "\"15%2F5=y\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=3%29\"\r
\n" ); document.write( "\n" ); document.write( "now substitute it in \"x=10-2y\" and find \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=10-2%2A3\"\r
\n" ); document.write( "\n" ); document.write( "\"x=10-6\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=4%29\"\r
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