document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007435>Question 1007435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist leaves town a heading east at the same time another cyclist leaves town B ,60 kilometers away heading west on the same highway the east bound cyclist can average 25 kph the other cyclist can average only 15 kph the cyclist ride until they meet how long does it take?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629352 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The distance between them is 60 km.<BR>\n" );
document.write( "The rate at which these cyclists close that distance is 15+25 = 40 kph.<BR>\n" );
document.write( "Of course, distance is rate times time, or d=rt.<BR>\n" );
document.write( "Then t = d/r = 60/40 = 1.5 hours. </SPAN>\n" );
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