document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008455>Question 1008455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference of twice one number and five time another number is 11. The first number is three time the second number increased by 6. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629349 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the first and second numbers, x and y.  Then we write<BR>\n" );
document.write( "2x - 5y = 11  and<BR>\n" );
document.write( "x = 3y + 6<BR>\n" );
document.write( "Now substitute the second equation into the first and get<BR>\n" );
document.write( "2(3y+6) - 5y = 11<BR>\n" );
document.write( "6y + 12 - 5y = 11<BR>\n" );
document.write( "y + 12 = 11<BR>\n" );
document.write( "y = -1  and<BR>\n" );
document.write( "x = 3(-1) + 6 = 3<BR>\n" );
document.write( "Your numbers are 3 and -1. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );