document.write( "Question 1013138: $0.60x+$2y=$200
\n" ); document.write( "x+y=178\r
\n" ); document.write( "\n" ); document.write( "Please explain how to solve a system of linear equations for whatever method you chose. I am new to this. \r
\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #629319 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
See the other example you asked for a few minutes ago. The method (substitution used) can work the same way. (I had solved for one of the variables, but for the other variable, I merely did not finish the computation).\r
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\n" ); document.write( "\n" ); document.write( "\"0.60\"-----Another way to manage this is, understand meaning of decimals.
\n" ); document.write( "\"0.60=60%2F100=6%2F10=%282%2A3%29%2F%282%2A5%29\"
\n" ); document.write( "\"%282%2F2%29%283%2F5%29\"
\n" ); document.write( "\"1%2A%283%2F5%29\"
\n" ); document.write( "\"3%2F5\".\r
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\n" ); document.write( "\n" ); document.write( "That money equation is therefore equivalent to \"%283%2F5%29x%2B2y%2B200\".
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