document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007435>Question 1007435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist leaves town a heading east at the same time another cyclist leaves town B ,60 kilometers away heading west on the same highway the east bound cyclist can average 25 kph the other cyclist can average only 15 kph the cyclist ride until they meet how long does it take?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629316 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The cyclist approach one another at:<BR>\n" );
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document.write( "15kph+25kph=40kph<BR>\n" );
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document.write( "To travel 60 km:<BR>\n" );
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document.write( "60km/40kph=1.5 hours<BR>\n" );
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document.write( "ANSWER: They will meet in 1.5 hours. </SPAN>\n" );
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