document.write( "Question 1008675: Mr. Martin traveled to a city 150 miles from his home to attend a meeting. Due to car trouble, his average speed returning was 10 mph less than his speed going. If the total time for the round trip was 5 hours, at what rate of speed did he travel to the city? (Round your answer to the nearest tenth.) \n" ); document.write( "
Algebra.Com's Answer #629306 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "R=rate going to other city
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\n" ); document.write( "\"150mi%2FR%2B150mi%2F%28R-10%29=5\"
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\n" ); document.write( "\"%28%28150mi%29%28R-10%29%2B%28150mi%29%28R%29%29%2F%28R%29%28R-10%29=5\"
\n" ); document.write( "\"150R-1500%2B150R=5%28R%29%28R-10%29\"
\n" ); document.write( "\"300R-1500=5R%5E2-50R\"
\n" ); document.write( "\"0=5R%5E2-350R%2B1500\"
\n" ); document.write( "\"0=R%5E2-70R%2B300\"
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aR%5E2%2BbR%2Bc=0\" (in our case \"1R%5E2%2B-70R%2B300+=+0\") has the following solutons:
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\n" ); document.write( " \"R%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-70%29%5E2-4%2A1%2A300=3700\".
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\n" ); document.write( " Discriminant d=3700 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--70%2B-sqrt%28+3700+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"R%5B1%5D+=+%28-%28-70%29%2Bsqrt%28+3700+%29%29%2F2%5C1+=+65.4138126514911\"
\n" ); document.write( " \"R%5B2%5D+=+%28-%28-70%29-sqrt%28+3700+%29%29%2F2%5C1+=+4.5861873485089\"
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\n" ); document.write( " Quadratic expression \"1R%5E2%2B-70R%2B300\" can be factored:
\n" ); document.write( " \"1R%5E2%2B-70R%2B300+=+1%28R-65.4138126514911%29%2A%28R-4.5861873485089%29\"
\n" ); document.write( " Again, the answer is: 65.4138126514911, 4.5861873485089.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-70%2Ax%2B300+%29\"

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\n" ); document.write( "Since 4.5 does not work (returning was 10 mph less would
\n" ); document.write( "result in negative speed), his rate going to the city was
\n" ); document.write( "65.4 mph.
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\n" ); document.write( "ANSWER: His rate traveling to the city was 65.4 mph
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\n" ); document.write( "CHECK:
\n" ); document.write( "150 mi/65.4mph+150mi/55.4mph = 5 hours
\n" ); document.write( "2.29 hours + 2.71 hours = 5 hours
\n" ); document.write( "5 hours = 5 hours
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