document.write( "Question 1008675: Mr. Martin traveled to a city 150 miles from his home to attend a meeting. Due to car trouble, his average speed returning was 10 mph less than his speed going. If the total time for the round trip was 5 hours, at what rate of speed did he travel to the city? (Round your answer to the nearest tenth.) \n" ); document.write( "
Algebra.Com's Answer #629306 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "R=rate going to other city \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( ". \n" ); document.write( "Since 4.5 does not work (returning was 10 mph less would \n" ); document.write( "result in negative speed), his rate going to the city was \n" ); document.write( "65.4 mph. \n" ); document.write( ". \n" ); document.write( "ANSWER: His rate traveling to the city was 65.4 mph \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "150 mi/65.4mph+150mi/55.4mph = 5 hours \n" ); document.write( "2.29 hours + 2.71 hours = 5 hours \n" ); document.write( "5 hours = 5 hours \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |