document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013114>Question 1013114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If tanx is 3/4, with the triangle in the third quadrant, what is sin(x/2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629290 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If tan(t) is 3/4, with the triangle in the third quadrant, what is sin(t/2)? <BR>\n" );
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document.write( "sin(t/2) = sqrt[(1-cos(t))/2]<BR>\n" );
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document.write( "If tan(t) = 3/4, y = -3 and x = -4, since t is in QIII.<BR>\n" );
document.write( "Then r = sqrt(3^2+4^2) = sqrt[25] = 5<BR>\n" );
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document.write( "So cos(t) = -4/5<BR>\n" );
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document.write( "Ans: sin(t/2) = sqrt[(1+(4/5))/2] = sqrt[9/10] = 3/sqrt(10)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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