document.write( "Question 1013107: In the figure plane E is parallel to plane F, AB is perpendicular to F and AG is the perpendicular bisector of CD. If m∠C-AB-D = 30, what is m∠BDC?
\n" ); document.write( "Image: https://gyazo.com/d2c76b9ec1433620e10a45ca1461bd86
\n" ); document.write( "Last 2 tutors were absolutely useless, they told me I'm wrong, please help me with this, take a look at the gyazo for clarification. Do not ask me what m∠C-AB-D = 30 means. How the hell am I supposed to know? I'm giving a screenshot for a reason. The teacher gave us a packet to finish as a midterm review guide but this question makes no sense.
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Algebra.Com's Answer #629277 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "E || F
\n" ); document.write( "AB is perpendicular to F, => AB is perpendicular to E because E || F
\n" ); document.write( "AG is the perpendicular bisector of CD-> I think it should be BG is the perpendicular bisector of CD\r
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\n" ); document.write( "\n" ); document.write( "If $\"m\"$ < $\"C-AB-D+=+30\"$ (this is angle between line segment AB and plane in which triangle ACD lie), is same as $\"m\"$

and $\"AB\"$ )\r
\n" ); document.write( "\n" ); document.write( "since $\"BG\"$ is the perpendicular bisector of $\"CD\"$ , means line segment $\"CG=GD\"$ , consequently $\"BC=BD\"$ ; so, triangle $\"BCD\"$ is divided into two right triangles by $\"+BG+\"$
\n" ); document.write( "then we know that:
\n" ); document.write( "1. measure of angles vertex $\"B\"$ and $\"G\"$ is $\"90+\"$
\n" ); document.write( "2. sides $\"BC\"$ and $\"BD\"$ are equal in length, then triangles $\"ABG\"$ , $\"BCG\"$ , and $\"BGD\"$ are right triangles which are $\"similar\"$ \r
\n" ); document.write( "\n" ); document.write( "take a look at similar triangles $\"ABG\"$ and $\"BGD\"$ :\r
\n" ); document.write( "\n" ); document.write( "angles vertex $\"B\"$ and $\"G\"$ are both $\"90+\"$
\n" ); document.write( " $\"AG\"$ corresponds to $\"BD\"$
\n" ); document.write( " $\"GD+\"$ correspond to $\"AB\"$
\n" ); document.write( " $\"+BG+\"$ is common side \r
\n" ); document.write( "\n" ); document.write( "if $\"AG\"$ corresponds to $\"BD\"$ and $\"m\"$ < $\"ABG+=30\"$ , then the $\"m\"$ < $\"GBD+=30\"$ too\r
\n" ); document.write( "\n" ); document.write( "consequently\r
\n" ); document.write( "\n" ); document.write( " $\"m\"$ < $\"BDC+=60\"$ \r
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