document.write( "Question 1013078: Hi! The problem is: An ice cream parlor makes $200. They sell cups of ice cream for $0.60 and cones for $2. How much cups of ice cream did they sell? How much cones of ice cream did they sell? \r
\n" ); document.write( "\n" ); document.write( "Thanks so much for your help! \r
\n" ); document.write( "\n" ); document.write( "I've tried to divide $200 by 0.60 but what about the cones?
\n" ); document.write( "

Algebra.Com's Answer #629262 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+a+\" = number of cups of ice cream sold
\n" ); document.write( "Let \"+b+\" = number of cones sold
\n" ); document.write( "--------------------------------
\n" ); document.write( "(1) \"+.6a+%2B+2b+=+200+\"
\n" ); document.write( "(1) \"+6a+%2B+20b+=+2000+\"
\n" ); document.write( "(1) \"+3a+%2B+10b+=+1000+\"
\n" ); document.write( "----------------------
\n" ); document.write( "You need another equation to actually solve this.
\n" ); document.write( "You have 2 unknowns and only 1 equation
\n" ); document.write( "----------------------
\n" ); document.write( "\"+a+\" has to be a multiple of \"+10+\", since
\n" ); document.write( "that's the only way to end up with \"+0+\" in the
\n" ); document.write( "units digit of \"+200+\"
\n" ); document.write( "So, there are many possible answers:
\n" ); document.write( "\"+3%2A10+%2B+10b+=+1000+\"
\n" ); document.write( "\"+3%2A20+%2B+10b+=+1000+\"
\n" ); document.write( "\"+3%2A30+%2B+10b+=+1000+\"
\n" ); document.write( "etc.
\n" ); document.write( "Find \"+b+\" for each equation
\n" ); document.write( "------------
\n" ); document.write( "But the problem is still that you are missing data
\n" ); document.write( "
\n" );