document.write( "Question 1013018: Find four roots of the following equation:\r
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\n" ); document.write( "\n" ); document.write( "* I plugged into my calculator and only got 2 roots, x=-3 and x=3, but how do you get the rest? Thanks :)
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Algebra.Com's Answer #629171 by ikleyn(52799)\"\" \"About 
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\n" ); document.write( "Find four roots of the following equation:\r
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document.write( "Introduce new variable for your convenience, y = \"x%5E2\".\r\n" );
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document.write( "Then your equation takes the form\r\n" );
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document.write( "\"2y%5E2+%2B+5y+-+207\" = \"0\".\r\n" );
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document.write( "Apply the quadratic formula. You will get\r\n" );
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document.write( "\"y%5B1%2C2%5D\" = \"%28-5+%2B-+sqrt%2825+%2B4%2A2%2A207%29%29%2F4%29\" = \"%28-5+%2B-+sqrt%281681%29%29%2F4\" = \"%28-5+%2B-+41%29%2F4\".\r\n" );
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document.write( "So, \"y%5B1%5D\" = 9, \"y%5B2%5D\" = \"-23%2F2\".\r\n" );
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document.write( "Now you need to solve this two quadratic equations:\r\n" );
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document.write( "1)  \"x%5E2\" = 9. It has two solutions:  x = \"3\"  and  x = \"-3\".\r\n" );
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document.write( "2)  \"x%5E2\" = \"-23%2F2\". It has two solutions:  x = \"i%2Asqrt%2823%2F2%29\"  and  x = \"-i%2Asqrt%2823%2F2%29\".\r\n" );
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document.write( "Thus you got four solutions of your original equation.\r\n" );
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