document.write( "Question 1012958: Twice Amy's age is 5 years more than that of Betty's. Twice the square of Amy's age subtracted from the square of Betty's age is 7 years. Find the sum of their ages. \n" ); document.write( "
Algebra.Com's Answer #629130 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A=Amy's age; B=Betty's age \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Since twice Amy's age is 5 more than Betty's age, 1 does not work: \n" ); document.write( ". \n" ); document.write( "2A-5=B \n" ); document.write( "2(1)-5=B \n" ); document.write( "2-5=B \n" ); document.write( "-3=B \n" ); document.write( ". \n" ); document.write( "And Betty cannot be -3 years old. \n" ); document.write( ". \n" ); document.write( "So Amy is 9 years old. \n" ); document.write( ". \n" ); document.write( "B=2A-5 \n" ); document.write( "B=2(9)-5 \n" ); document.write( "B=16-5=13 \n" ); document.write( "Betty is 13 years old. \n" ); document.write( ". \n" ); document.write( "A+B=9+13=22 \n" ); document.write( "ANSWER: The sum of their ages is 22 years \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |