document.write( "Question 1012974: Ann had a bag of glass beads. She used half of them to make a necklace. She and her sister used 1/6 and 1/7 of the remaining beads to make bracelets. If 58 beads were left, find the original number of beads. \n" ); document.write( "
Algebra.Com's Answer #629122 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "x=half original beads; 2x=original number of beads \n" ); document.write( ". \n" ); document.write( "x=(1/6)x+(1/7)x+58 \n" ); document.write( "x=(7/42)x+(6/42)x+58 \n" ); document.write( "x=(13/42)x+58 \n" ); document.write( "(29/42)x=58 \n" ); document.write( "x=(42/29)(58) \n" ); document.write( "x=64 \n" ); document.write( "She had 84 beads left after she made the necklace \n" ); document.write( ". \n" ); document.write( "Original number=2x=2(84)=168 \n" ); document.write( ". \n" ); document.write( "ANSWER: She originally had 168 beads. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |