document.write( "Question 1012979: The perimeter of a rectangle is 42 cm. If the length is trebled and 7cm is added to 4 times the width, the perimeter of the new rectangle is 154 cm. Find the length of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #629118 by macston(5194)\"\" \"About 
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\n" ); document.write( "L=original length; W=original width;P=original perimeter
\n" ); document.write( "P2=perimeter of new rectangle
\n" ); document.write( ".
\n" ); document.write( "\"P=2%28L%2BW%29\"
\n" ); document.write( "\"42cm=2%28L%2BW%29\"
\n" ); document.write( "\"21=L%2BW\"
\n" ); document.write( "\"21-W=L\" Use this to substitute below.
\n" ); document.write( ".
\n" ); document.write( "\"P2=2%283L%2B4W%2B7%29\"
\n" ); document.write( "\"154cm=2%283L%2B4W%2B7%29\"
\n" ); document.write( "\"77=3L%2B4W%2B7\"
\n" ); document.write( "\"77=3L%2B4W%2B7\" Substitute for L from above.
\n" ); document.write( "\"77=3%2821-W%29%2B4W%2B7\"
\n" ); document.write( "\"70=63-3W%2B4W\"
\n" ); document.write( "\"7=W\"
\n" ); document.write( ".
\n" ); document.write( "ANSWER 1: The original width was 7 cm.
\n" ); document.write( ".
\n" ); document.write( "\"L=21-W\"=\"21-7=14\"
\n" ); document.write( "ANSWER 2: The original length was 14 cm.
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\n" ); document.write( "CHECK:
\n" ); document.write( ".
\n" ); document.write( "\"P=2%28L%2BW%29\"
\n" ); document.write( "\"P=2%2814cm%2B7cm%29\"
\n" ); document.write( "\"42cm=2%2821cm%29\"
\n" ); document.write( "\"42cm=42cm\"
\n" ); document.write( ".
\n" ); document.write( "\"P2=2%283L%2B%284W%2B7%29%29\"
\n" ); document.write( "\"154cm=2%283%2814cm%29%2B4%287cm%29%2B7cm%29\"
\n" ); document.write( "\"154cm=2%2842cm%2B28cm%2B7cm%29\"
\n" ); document.write( "\"154cm=2%2877cm%29\"
\n" ); document.write( "\"154cm=154cm\"
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