document.write( "Question 1012955: : To complete a work 'A' takes 50% more time than 'B'. If together they take 18 days to complete the work, how much time will 'B' take to do it? \n" ); document.write( "
Algebra.Com's Answer #629098 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! To complete a work 'A' takes 50% more time than 'B'. \n" ); document.write( " If together they take 18 days to complete the work, how much time will 'B' take to do it? \n" ); document.write( ": \n" ); document.write( "let b = time required by B to do the job \n" ); document.write( "\"To complete a work 'A' takes 50% more time than 'B'\"; therefore \n" ); document.write( "1.5b = Time required by A to do the job \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( "Each will do a fraction of the job, the two fractions add up to 1 \n" ); document.write( " \n" ); document.write( "Get rid of the fractions, multiply equation by 3b \n" ); document.write( "3b* \n" ); document.write( "Cancel the denominators \n" ); document.write( "2(18) + 3(18) = 3b \n" ); document.write( "36 + 54 = 3b \n" ); document.write( "90 = 3b \n" ); document.write( "b = 90/3 \n" ); document.write( "b = 30 hrs required by B to do the job alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "using a calc \n" ); document.write( ".4 + .6 = 1 \n" ); document.write( " |