document.write( "Question 1012932: Two mechanics worked on a car. The first mechanic worked for 5 hours, and the second mechanic worked for 15 hours. Together they charged a total of 1850. What was the rate charged per hour by each mechanic if the sum of the two rates was 160 per hour? \n" ); document.write( "
Algebra.Com's Answer #629063 by macston(5194) You can put this solution on YOUR website! . \n" ); document.write( "F=hourly rate for first mechanic; S=hourly rate for second mechanic \n" ); document.write( ". \n" ); document.write( "F+S=160 \n" ); document.write( "F=160-S \n" ); document.write( ". \n" ); document.write( "5F+15S=1850 \n" ); document.write( "5(160-S)+15S=1850 \n" ); document.write( "800-5S+15S=1850 \n" ); document.write( "10S=1050 \n" ); document.write( "S=105 \n" ); document.write( "ANSWER 1: The second mechanic charged 105 per hour. \n" ); document.write( ". \n" ); document.write( "F=160-F=160-105=55 \n" ); document.write( "ANSWER 2: The first mechanic charged 55 per hour. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "5F+15S=1850 \n" ); document.write( "5(55)+15(105)=1850 \n" ); document.write( "275+1575=1850 \n" ); document.write( "1850=1850 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |