document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012921>Question 1012921</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Olivia has $30 more than Carl. if they each had $7 less, the sum of the funds would equal the amount that olivia has now. how much money does each have now........ please show steps!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629046 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call what Olivia and Carl have, x and y.  Thus we have<BR>\n" );
document.write( "x = y + 30  and<BR>\n" );
document.write( "(x - 7) + (y - 7) = x<BR>\n" );
document.write( "A few ways to solve this, but let us substitute the first equation into the second and we get<BR>\n" );
document.write( "(y+30 - 7) + (y - 7) = y + 30<BR>\n" );
document.write( "2y + 16 = y + 30<BR>\n" );
document.write( "Now subtract y from both sides, then subtract 16...<BR>\n" );
document.write( "y + 16 = 30<BR>\n" );
document.write( "y = $14 for Carl<BR>\n" );
document.write( "x = y + 30 = $44 for Olivia </SPAN>\n" );
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