document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012922>Question 1012922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 73. when the smaller number is subtracted from twice the greater number the result is 50. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629043 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the larger and smaller, x and y.  Thus we have<BR>\n" );
document.write( "x + y = 73  and<BR>\n" );
document.write( "2x - y = 50<BR>\n" );
document.write( "Now add these equations and get<BR>\n" );
document.write( "3x = 123<BR>\n" );
document.write( "x = 41<BR>\n" );
document.write( "Thus y must be 73-41 or<BR>\n" );
document.write( "y = 32 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );