document.write( "Question 1012843: Sine theta = cos(2 theta-10) \n" ); document.write( "
Algebra.Com's Answer #629027 by ikleyn(52925)\"\" \"About 
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\n" ); document.write( "Sine theta = cos(2 theta-10)
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document.write( "\"sin%28theta%29\" = \"cos%282%2Atheta-10%29\".   (1)\r\n" );
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document.write( "I don't know exactly what is 10: radians or degrees? Will suppose degrees.\r\n" );
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document.write( "We all know that\r\n" );
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document.write( "\"sin%28theta%29%29%29\" = \"cos%2890%5Eo-theta%29\".\r\n" );
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document.write( "Combining this with (1), you will get\r\n" );
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document.write( "\"cos%282%2Atheta-10%5Eo%29\" = \"cos%2890%5Eo-theta%29\".\r\n" );
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document.write( "It implies that \r\n" );
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document.write( "\"2%2Atheta-10%5Eo\" = \"90%5Eo-theta\".   (2)\r\n" );
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document.write( "Not exactly, because you should remember about +/-\"2k%2Api\" and other similar additional terms, \r\n" );
document.write( "but I am going to give only the \"naive\" solution here.\r\n" );
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document.write( "From (2) you have\r\n" );
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document.write( "\"3%2Atheta\" = 90° +10° = 100°.   Hence \"theta\" = \"1%2F3\".100°.\r\n" );
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