document.write( "Question 1012876: 2 parties each hold 6 people in how many ways can a party of 6 boys and 6 girls divide themselves so that they're equal number of boys and girls in each party? \n" ); document.write( "

Algebra.Com's Answer #629021 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "2 parties each hold 6 people in how many ways can a party of 6 boys and 6 girls divide themselves so that they're equal number of boys and girls in each party?
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document.write( "You can choose 3 boys of 6 for the first party by  =  = 20 ways.\r\n" );
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document.write( "You can choose 3 girls of 6 for the first party by  =  = 20 ways.\r\n" );
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document.write( "In total, you have 20*20 ways to choose 3 boys of 6 and 3 girls of 6 for the first party. \r\n" );
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document.write( "The rest of the boys and the girls will participate in the 2nd party without choice.\r\n" );
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